Question

A population of squirrels grows exponentially at a rate of 4.2 percent per year. The population was 8400 in 2002. Step 1 of 3: Find the exponential function that represents the population t years after 2002. Answer Point f(t) =

Answer 1

P(t) = 8,400e^(0.042)t

P(t) = total population t years after 2002

8,400 initial population at 2002

0.042 = rate of growth

t = #years after 2002

Explanation:

Using the formula for exponential growth, in this case P(t) = P(subscript 0) e^(kt), k as rate.

P(subscript 0) initial population = 8400

k rate = 4.2% = 0.042

Plug in the numbers as given by the problem.