Answer: stated down below
Step-by-step explanation:
To solve this problem, we can use trigonometry and related rates.
Let's define the following variables:
h: altitude of the plane from the ground radar station (in km)
d: horizontal distance from the plane to the radar station (in km)
Given:
The plane is flying at a constant speed of 360 km/h.
The altitude of the plane is 1 km.
The plane climbs at an angle of 30°.
We want to find the rate at which the distance from the plane to the radar station is increasing a minute later.
First, let's consider the right triangle formed by the plane, the radar station, and the distance the plane has traveled in one minute (which is equal to its speed, 360 km/h).
In this right triangle, the angle between the hypotenuse (the distance the plane has traveled in one minute) and the base (horizontal distance d) is 30°. The opposite side of this angle is the altitude of the plane, h.
Using trigonometry, we can write the following equation:
tan(30°) = h / d
tan(30°) = (1 km) / d
√3/3 = 1 / d
d = 3 / √3 = √3 km
Now, to find the rate at which the distance is increasing, we need to differentiate the equation with respect to time.
Differentiating both sides with respect to time:
d/dt (d) = d/dt (√3 km)
The derivative of d with respect to time represents the rate at which the distance is changing, which is what we want to find.
Since the speed of the plane is constant at 360 km/h, the derivative of d with respect to time is equal to the speed:
d/dt (d) = 360 km/h
Therefore, the rate at which the distance from the plane to the radar station is increasing a minute later is approximately 360 km/h (rounded to the nearest whole number).
Note: The rate of increase of the distance is independent of the altitude of the plane.