Question

I am extremely confused about this problem. What is the answer and what would be the best way to solve it? The problem is linked below.

Answer 1

2ab³

Explanation:

evaluate the radical inside the parenthesis

`\sqrt[3]{64a^6b^(18) }`

=
`\sqrt[3]{64}` ×
`\sqrt[3]{a^6}` ×
`\sqrt[3]{b^(18) }`

= 4 × a² ×
`b^(6)`

= 4a²
`b^(6)`

note that
`a^{(1)/(2) }` =
`√(a)`

then

`4a^2b^6)^{(1)/(2) }`

=
`√(4)` ×
`√(a^2)` ×
`√(b^6)`

= 2 × a × b³

= 2ab³