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Event A: the coin lands on heads
Event B: the die is 3 or greater
P(A and B)=

1 Answer

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Since the events are independent,
P(A\cap B)=P(A)\cdot P(B).


A - the coin lands on heads


|\Omega|=2\\|A|=1\\\\P(A)=(1)/(2)


B - the die is 3 or greater


|\Omega|=6\\|B|=4\\\\P(B)=(4)/(6)=(2)/(3)

Therefore


P(A\cap B)=(1)/(2)\cdot(2)/(3)=(1)/(3)

User Sreenivas
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