Question

An elevator descends into a mine shaft at the rate of 6 cm/sec. If it starts from 100 cm below ground level, how long will it take to reach 216 cm below ground level?

Answer 1

100 + 6s = 216

6s = 116

s = 19 1/3 seconds

Answer 2

Answer: 19 seconds

Explanation:

The elevator will travel a distance of:

• 216 - 100 = 116 cm.

Since the elevator travels at a rate of 6 cm/sec:

• 116 ÷ 6 = 19 (rounded to the nearest whole number)

It will take 19 seconds to reach 216 cm below ground level.

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