Question

3 years ago, the population of a village was 37000. The rate of population growth is 3%. But, one year ago, 696 people died of epidemic disease,

(a) Find the population before one year. (b) What is the present population of the village?
(c) 6040 people migrated in the beginning of this year then what will be the population of the village after 2 years at the same growth rate​

Answer 1

(a) To find the population before one year, we need to account for the population growth rate of 3% per year and the number of deaths due to the epidemic.

First, let's calculate the population before the epidemic by taking into account the 3% growth rate for three years. We can use the formula for compound interest:

Population before epidemic = Population after three years / (1 + growth rate)^number of years

Population before epidemic = 37000 / (1 + 0.03)^3

Simplifying this calculation, we get:

Population before epidemic = 37000 / (1.03)^3

Population before epidemic ≈ 33942.91 (approximately)

(b) To find the present population of the village, we need to consider the population before the epidemic and account for the deaths of 696 people.

Present population = Population before epidemic - Number of deaths

Present population ≈ 33942.91 - 696

Present population ≈ 33246.91 (approximately)

Therefore, the present population of the village is approximately 33,246.

(c) To calculate the population after 2 years, we need to consider the present population and the migration of 6040 people at the beginning of the year.

Population after 2 years = Present population + Number of migrants

Population after 2 years ≈ 33246.91 + 6040

Population after 2 years ≈ 39286.91 (approximately)

Therefore, the population of the village after 2 years, considering the growth rate, deaths, and migration, is approximately 39 287.

.

Explanation: