41.7k views
4 votes
Find the range of y =
2^( x)

Find the range of y =
2 ^( - x)
Please help!​

2 Answers

5 votes

Explanation:

y = 2^x. y>0 is the range (0, ♾️)

y = 2^-x. y >0 is the range. (0, ♾️)

User Yochi
by
8.0k points
4 votes

Answer:

Range of y = 2^x is all positive real numbers.

Range of the function y = 2^{-x} is all positive real numbers excluding zero

Explanation:

Find the range of y = 2^x

Answer:

  • Since 2^x is an exponential function with a base of 2, the function will always output positive values.

This means that the range of y is all positive real numbers, or y > 0.

In mathematical notation, we can express the range as:


y \in (0, \infty)

Therefore, the range of y = 2^x is all positive real numbers .


\hrulefill

Find the range of y = 2^(-x)

Answer:

Since 2^{-x} represents the reciprocal of 2^x, the function will output positive values as the exponent becomes more negative.

  • As x approaches positive infinity
    x \to \infty, the value of 2^{-x} approaches 0.
  • As x approaches negative infinity
    x \to -\infty, the value of 2^{-x} approaches positive infinity.

Therefore, the range of the function y = 2^{-x} is all positive real numbers greater than zero, but does not include zero itself.

In mathematical notation, we can express the range as:


y \in (0, \infty)

Therefore, range of the function y = 2^{-x} is all positive real numbers excluding zero.

User Soham
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories