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A math teacher earned $48,000 in their first year of teaching and a 5% raise each successive year. In her 10th year she earned Blank 1 ? Over a 10 year period she earned Blank 2.

A math teacher earned $48,000 in their first year of teaching and a 5% raise each-example-1

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Alright, let's break it down step by step.

The math teacher earned $48,000 in her first year. She then gets a 5% raise each year after that. This is an example of what we call a "geometric sequence" in mathematics, where each term is a fixed percentage of the term before it.

Let's first figure out how much she earned in her 10th year.

To calculate her salary for a given year, we can use the formula:

Salary = Initial Salary * (1 + raise rate)^(number of years - 1)

For the 10th year, the number of years is 10, the initial salary is $48,000, and the raise rate is 5%, which is equal to 0.05 when expressed as a decimal.

Plugging these values into the formula:

Salary in 10th year = $48,000 * (1 + 0.05)^(10 - 1)

= $48,000 * (1.05)^9

= $48,000 * 1.5513 (rounded to four decimal places)

≈ $74,461.44

So, in her 10th year, she earned approximately $74,461.44.

Now, let's calculate the total earnings over the 10-year period.

To do this, we can use the formula for the sum of a geometric sequence:

Total Earnings = Initial Salary * ( (1 + raise rate)^number of years - 1 ) / raise rate

Plugging in the values:

Total Earnings = $48,000 * ( (1.05)^10 - 1 ) / 0.05

= $48,000 * (1.6289 - 1) / 0.05 (rounded to four decimal places)

= $48,000 * 12.5778 (rounded to four decimal places)

≈ $603,734.40

So, over a 10-year period, she earned approximately $603,734.40.

I hope that helps! Let me know if you have any more questions or need further clarification on anything.

User Sander Schaeffer
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