Question

Find the root(s) of f(x) = (x+5)3(x-9)2(x+1)

Answer 1

the roots of f(x) = (x+5)3(x-9)2(x+1) are -5 (with a multiplicity of 3), 9 (with a multiplicity of 2)

Explanation:

To find the roots of f(x) = (x+5)3(x-9)2(x+1), we need to set the polynomial equal to zero and solve for x.

f(x) = (x+5)3(x-9)2(x+1)

Setting f(x) equal to zero, we get:

0 = (x+5)3(x-9)2(x+1)

The roots of the polynomial are the values of x that make f(x) equal to zero. Therefore, the roots of the polynomial are:

-5 (with a multiplicity of 3), 9 (with a multiplicity of 2), and -1

Therefore, the roots of f(x) = (x+5)3(x-9)2(x+1) are -5 (with a multiplicity of 3), 9 (with a multiplicity of 2),