Question

A train is by moving with the velocity 10m/s. It attains an acceleration of 4m/s^2 after 5 seconds. Find the distance covered by the train in that time.

Ans:10m/s


Please help me please

Answer 1

`\huge\boxed{\sf S = 100\ m}`

Step-by-step explanation:

Given data:

Initial velocity =
`V_i` = 10 m/s

Acceleration = a = 4 m/s²

Time = t = 5 s

Required:

Distance = S = ?

Formula:

`\displaystyle S = V_i t + (1)/(2) at^2` (Second equation of motion)

Solution:

Plug in the above given values.

S = (10)(5) + 1/2 (4)(5)²

S = 50 + (2)(25)

S = 50 + 50

S = 100 m

`\rule[225]{225}{2}`