Question

The temperature of a aluminum bar rises by 10.0°C when it absorbs 4.73 kJ of energy by heat. The mass of the bar is 525 g. Determine the specific heat of aluminum from these data. Answer is in kJ/kg · °C.

Answer 1

Certainly! We can use the formula:

q = mcΔT

where q is the amount of heat absorbed, m is the mass of the aluminum bar, c is the specific heat capacity of aluminum, and ΔT is the change in temperature.

Substituting the given values, we get:

4.73 kJ = (0.525 kg) x c x (10.0°C)

Solving for c, we get:

c = 0.901 kJ/kg · °C

Therefore, the specific heat of aluminum is 0.901 kJ/kg · °C.

Step-by-step explanation: