Answer:
y = 4(x + 1)² - 1
Explanation:
the equation of a quadratic function in vertex form is
y = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
here (h, k ) = (- 1, - 1 ), then
y = a(x - (- 1) )² - 1 , that is
y = a(x + 1)² - 1
to find a substitute the coordinates of any other point on the graph into the equation.
using (0, 3 )
3 = a(0 + 1)² - 1 ( add 1 to both sides )
4 = a(1)² = a
y = 4(x + 1)² - 1 ← in vertex form