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Find Vertex and show steps. y = 2x^2 + 8x - 2

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Answer:Here are the steps to find the vertex of the quadratic equation y = 2x^2 + 8x - 2:

The vertex form of a quadratic equation is:

y = a(x- h)^2 + k

Where (h,k) are the coordinates of the vertex.

In this equation, a = 2, b = 8, c = -2. To find the vertex (h,k):

h = -b / (2a)

= -8 / (2(2))

= -2

k = y when x = h

= y when x = -2

Substitute x = -2 into the original equation:

y = 2(-2)^2 + 8(-2) - 2

= 8 - 16 - 2

= -10

Therefore, the vertex of this parabola is:

(h,k) = (-2, -10)

We can verify this graphically:

Plugging y = 2x2 + 8x - 2 into a graphing calculator and adding the point (-2, -10), we can see that the point sits at the bottom of the parabola, verifying it is the vertex.

So in summary, the vertex of the quadratic equation y = 2x^2 + 8x - 2 is:

(-2, -10)

Hope this explanation of the steps and solution is helpful! Let me know if you have any other questions.

Explanation:

User Yovanny
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