Question

A gas is initially at 800. 0 mL and

115 °C. What is the new

temperature if the gas volume

shrinks to 400. 0 mL?

Answer 1

-79.15

Step-by-step explanation:

-79.15 is correct on acellus

Answer 2

`\huge\boxed{\sf T_2 = 194 \ K}`

Step-by-step explanation:

Given data:

Initial Volume = V1 = 800 mL

Initial Temperature = T1 = 115 + 273 = 388 K

Final Volume = V2 = 400 mL

Required:

Final Temperature = T2 = ?

Formula:

`\displaystyle (V_1)/(T_1) = (V_2)/(T_2)` (Charles Law)

Solution:

Put the given data in the above formula.

`\displaystyle (800)/(388) = (400)/(T_2) \\\\Cross \ Multiply.\\\\800 * T_2 = 400 * 388\\\\800 * T_2 = 155200\\\\Divide \ both \ sides \ by \ 800.\\\\T_2 = (155200)/(800) \\\\T_2 = 194 \ K \\\\\rule[225]{225}{2}`