Question

A man on a motorcycle plans to make a jump as shown in the figure.

If he leaves the ramp with a speed of 31.5 m/s and has a speed of 29.3 m/s at the top of his trajectory, determine his maximum height (h) (in m) above the end of the ramp. Ignore friction and air resistance.

Answer 1

Answer:The maximum height (h) of the jump is 12.22 m above the end of the ramp.

The man on the motorcycle plans to make a jump with an initial speed of 33.0 m/s and a final speed of 31.5 m/s. The maximum height (h) of the jump can be calculated using the following equation:

h = (vi2 - vf2) / (2g)

where

vi is the initial speed,

vf is the final speed, and

g is the acceleration due to gravity (9.81 m/s2).

Plugging in the given values, we get:

h = (33.02 - 31.52) / (2 x 9.81)

h = 12.22 m

Therefore, the maximum height (h) of the jump is 12.22 m above the end of the ramp.

Step-by-step explanation: