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At a certain conference, three sessions were held at the same time period. The number of male and female

attendees at the three sessions was recorded, and the results are summarized below:

Session 1
Male 12
Female 8
Session 2
Male 18
Female 9
Session 3
Male 17
Female 5
a.) How many men attended the sessions?
b.) How many people attended Session 3?
c.) What is the sample size?
d.) If a random person is selected, what is the probability (to four decimal places) that the person is male?
e.) If a random person is selected, what is the probability (to four decimal places) that the person attended Session
3?
f.) If a random person is selected, what is the probability (to four decimal places) that the person is male and
attended Session 3?

Not multiple choice you have to work each question out!!

User Nazarudin
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1 Answer

2 votes

Answer:

Explanation:

A. 47 - s1-12, s2-18 s3-17 18+12+17=47

B. 17 men + 5 women = 22 people

C. 47(#of men)+women=total 5+8+9=22 47+22=69 total people

D. 0.6811%

E. 0.3188%
F. 0.2463%

User Michal Majka
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