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Need urgent help here-example-1

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Answer:


(6)/(25)

Explanation:


\mathrm{Solution,}\\\mathrm{Exhaustive\ number, n(S)=25}\\\mathrm{Favorable\ cases (E)={[(1,1),(2,2),(3,1),(1,3),(1,2),(2,1)]}}\\\mathrm{No.\ of\ favorable\ cases,n(E)=6\\}\\\therefore \mathrm{Probability\ of\ getting\ total\ of\ less\ than\ 5=(n(E))/(n(S))=(6)/(25)}

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