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5 votes
Solve and graph the following inequality: 4x + 5 >= 13

User Tizzick
by
7.6k points

2 Answers

4 votes

Answer:


\underline{\large\boxed{\sf{x\geqslant2}}}

Step-by-step explanation:

First, I am going to solve the inequality for x.

The inequality is:


\sf{4x+5\geqslant13}

I begin by subtracting 5 from each side:


\sf{4x\geqslant8}

Then, I divide each side by 4:


\sf{x\geqslant2}

Therefore,
\large\boxed{\sf{x\geqslant2}}

User GtotheB
by
7.7k points
5 votes

Answer:

x ≥ 2

Step-by-step explanation:

4x + 5 ≥ 13

4x ≥ 8

x ≥ 2

Solve and graph the following inequality: 4x + 5 >= 13-example-1
User Athar
by
8.5k points

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