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What is the area of a sector when 0=11pi/18 radians and r=6

What is the area of a sector when 0=11pi/18 radians and r=6
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What is the area of a sector when 0=11pi/18 radians and r=6

User Dolanor
by
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1 Answer

3 votes

Answer:

11π square units

Explanation:


\displaystyle A=(1)/(2)r^2\theta=(1)/(2)(6)^2\biggr((11\pi)/(18)\biggr)=11\pi

User Michael Ballent
by
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