34.0k views
4 votes
What is the correct range for the function ƒ(x) = x − 9 if the domain is (3, -3, 0) is

2 Answers

5 votes

Answer:

Explanation:

This Question is quite Easy, so

The correct answer for this function is as follows:

For finding the range of any function first we have to assume the whole range as y

y = x - 9

x = y + 9

Now to find the range ,we have to put the domain (3,-3,0) in place of y ,

x = 3 + 9 x = -3 + 9 x = 0 + 9

x = 12 x = 6 x = 9

so , the Range we got is,

(12 , 6 , 9)

User Delio
by
7.0k points
0 votes

Answer: -12, -9,-6

Explanation:

In this case, the function is ƒ(x) = x - 9, and the domain is (3, -3, 0).

When substituting the values, we get

For x = 3: ƒ(3) = 3 - 9 = -6

For x = -3: ƒ(-3) = -3 - 9 = -12

For x = 0: ƒ(0) = 0 - 9 = -9

Therefore, the correct range of the function ƒ(x) = x - 9, when the domain is (3, -3, 0), is -12, -9, -6.

User Flodin
by
8.3k points

No related questions found