Answer:
line EF
Explanation:
The slopes of perpendicular lines are negative reciprocals. Their product is -1. The given line has slope -1/3, so the line we are looking for has slope 3.
Slope AB (-3, 2), (3, 0)
m = (2 - 0)/(-3 - 3) = 2/(-6) = -1/3
Slope EF (0, -3), (2, 3)
m = (-3 - 3)/(0 - 2) = -6/(-2) = 3
Slope JK (-3, -4), (3, -2)
m = (-4 - (-2))/(-3 - 3) = -2/(-6) = 1/3
Slope MN (-1, 4), (2, -5)
m = (-5 - 4)/(2 - (-1)) = -9/3 = -3
The only line with slope = 3 is line EF.
Answer: line EF