Answer:
1) c) Q and S
2) d) SAS
3) a)
Explanation:
by ASA property
2) In ΔAED and ΔCEB
AE ≅ CE (AC is bisected)
ED ≅ EB (BD is bisected)
∠AED ≅ ∠CEB (vertically opposite)
⇒ ΔAED ≅ ΔCEB by SAS
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