Question

A lossless buck converter has the following known: Vin = 42V (input voltage) Vr­­_mx = 8 V (maximum ramp voltage) Kc = 12 (Controller proportional gain) Find the per cent error voltage?

Answer 1

The percent error voltage in the lossless buck converter is approximately -80.95%.

Step-by-step explanation:

The percent error voltage can be calculated using the known values. The formula for calculating percent error is given by:

Percent Error = (Measured Value - Actual Value) / Actual Value * 100%

In this case, the measured value is Vr­­_mx and the actual value is Vin. Plugging in the values:

Percent Error = (8 V - 42 V) / 42 V * 100% = -34/42 * 100% = -80.95%

Answer 2

The percent error voltage in this lossless buck converter is approximately 19.05%.

To solve this problem

We can use the following formula:

Percent Error Voltage =
`(Vr_m_x/ Vin) * 100`

Given:

Vin = 42V (input voltage)

`Vr_m_x` = 8V (maximum ramp voltage)

Substituting the values into the formula:

Percent Error Voltage = (8V / 42V) * 100

Now, let calculating the value:

Percent Error Voltage = (0.1905) * 100

Percent Error Voltage ≈ 19.05%

So, the percent error voltage in this lossless buck converter is approximately 19.05%.