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How many grams are there in each of the following? a) In 2.9 mol of lead. b) In 6.33 mol of dichlorine heptafluoride. c) In 8.25 mol of magnesium hydroxide. D) What is the mass of each of the following? a) 5.18x1025 atoms of calcium. b) 6.76x1022 molecules of tetraphosphorus decaoxide. c) 4.91x1023 formula units of aluminum oxide.

User Salmane
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Answer:

Step-by-step explanation:

To determine the mass in grams for each of the given substances, we need to use their respective molar masses. The molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol).

a) Lead (Pb) has a molar mass of approximately 207.2 g/mol. Therefore, the mass of 2.9 mol of lead is calculated as follows:

Mass = Number of moles × Molar mass

Mass = 2.9 mol × 207.2 g/mol

Mass ≈ 600.88 g

b) Dichlorine heptafluoride (Cl2F7) has a molar mass of approximately 265.77 g/mol. Thus, the mass of 6.33 mol of dichlorine heptafluoride is:

Mass = 6.33 mol × 265.77 g/mol

Mass ≈ 1,681.86 g

c) Magnesium hydroxide (Mg(OH)2) has a molar mass of approximately 58.33 g/mol. Hence, the mass of 8.25 mol of magnesium hydroxide is:

Mass = 8.25 mol × 58.33 g/mol

Mass ≈ 480.08 g

Moving on to the second part of the question:

a) To find the mass of 5.18 × 10^25 atoms of calcium (Ca), we need to know the atomic mass of calcium, which is approximately 40.08 g/mol. The mass can be calculated using the following steps:

Number of moles = Number of atoms / Avogadro's number

Number of moles = (5.18 × 10^25 atoms) / (6.022 × 10^23 mol^-1)

Number of moles ≈ 8.61 mol

Mass = Number of moles × Molar mass

Mass = 8.61 mol × 40.08 g/mol

Mass ≈ 344.83 g

b) Tetraphosphorus decaoxide (P4O10) has a molar mass of approximately 283.88 g/mol. The mass of 6.76 × 10^22 molecules of tetraphosphorus decaoxide can be calculated as follows:

Number of moles = Number of molecules / Avogadro's number

Number of moles = (6.76 × 10^22 molecules) / (6.022 × 10^23 mol^-1)

Number of moles ≈ 0.112 mol

Mass = Number of moles × Molar mass

Mass = 0.112 mol × 283.88 g/mol

Mass ≈ 31.82 g

c) Aluminum oxide (Al2O3) has a molar mass of approximately 101.96 g/mol. The mass of 4.91 × 10^23 formula units of aluminum oxide can be calculated as follows:

Number of moles = Number of formula units / Avogadro's number

Number of moles = (4.91 × 10^23 formula units) / (6.022 × 10^23 mol^-1)

Number of moles ≈ 0.815 mol

Mass = Number of moles × Molar mass

Mass = 0.815 mol × 101.96 g/mol

Mass ≈ 83.24 g

User Paul Johnston
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