Answer:
Step-by-step explanation:
To determine the number of carbon atoms in one dose of Bismuth subsalicylate (BiC7H5O4), we need to calculate the molar mass of BiC7H5O4 and then use the given mass of the dose to find the number of moles of BiC7H5O4. Finally, we'll multiply the moles by the number of carbon atoms in one molecule of BiC7H5O4.
The molar mass of BiC7H5O4 can be calculated as follows:
Bi: 1 atom × atomic mass of Bi = 1 × 208.98 g/mol = 208.98 g/mol
C: 7 atoms × atomic mass of C = 7 × 12.01 g/mol = 84.07 g/mol
H: 5 atoms × atomic mass of H = 5 × 1.01 g/mol = 5.05 g/mol
O: 4 atoms × atomic mass of O = 4 × 16.00 g/mol = 64.00 g/mol
Total molar mass of BiC7H5O4:
208.98 g/mol + 84.07 g/mol + 5.05 g/mol + 64.00 g/mol = 362.10 g/mol (rounded to two decimal places)
Given that the molar mass of BiC7H5O4 is 362.10 g/mol, we can calculate the number of moles in 524 mg (0.524 g) of BiC7H5O4 using the formula:
Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles = 0.524 g / 362.10 g/mol ≈ 0.001448 mol (rounded to six decimal places)
Finally, we can find the number of carbon atoms in one dose of BiC7H5O4 by multiplying the number of moles by the number of carbon atoms in one molecule of BiC7H5O4. In this case, there are 7 carbon atoms in each molecule of BiC7H5O4.
Number of carbon atoms = 0.001448 mol × 7 = 0.010136 (rounded to five decimal places)
Therefore, there are approximately 0.010136 carbon atoms in one dose (524 mg) of Bismuth subsalicylate (BiC7H5O4).