Answer:
v = ωr = (4.39 rad/s)(4.91 m) ≈ 21.54 m/s
Step-by-step explanation:
(a) To calculate the angular speed (ω) of the human centrifuge that results in a centripetal acceleration of 9g, we can use the formula for centripetal acceleration: a = ω²r, where a is the centripetal acceleration, ω is the angular speed, and r is the radius of the centrifuge. Solving for ω, we get:
ω = √(a/r) = √((9g)/r)
Substituting the values for g (9.8 m/s²) and r (4.91 m), we get:
ω = √((9 * 9.8 m/s²)/(4.91 m)) ≈ 4.39 rad/s
(b) To calculate the linear speed (v) of a person in the centrifuge at this acceleration, we can use the formula v = ωr, where v is the linear speed, ω is the angular speed, and r is the radius of the centrifuge. Substituting the values for ω (4.39 rad/s) and r (4.91 m), we get:
v = ωr = (4.39 rad/s)(4.91 m) ≈ 21.54 m/s