Answer:
x ≈ 14.2
Explanation:
assuming JK is a tangent then the angle between JK and the radius JL at the point of contact J is right.
then Δ JKL is a right triangle with hypotenuse KL
with KL = 7 + 11 = 18 ( internal part is a radius of the circle )
using Pythagoras' identity in the right triangle
JK² + JL² = KL² , that is
x² + 11² = 18²
x² + 121 = 324 ( subtract 121 from both sides )
x² = 203 ( take square root of both sides )
x =
≈ 14.2 ( to the nearest tenth )