Step-by-step explanation:
To calculate the equivalent resistance of the circuit below, we need to combine the resistors that are in series and in parallel.
Starting from the left, we see that the 10 Ω and 15 Ω resistors are in series, so we can combine them using the formula:
R_series = R1 + R2
R_series = 10 Ω + 15 Ω
R_series = 25 Ω
Next, we can combine the 20 Ω and 25 Ω resistors that are in parallel using the formula:
1/R_parallel = 1/R1 + 1/R2
1/R_parallel = 1/20 Ω + 1/25 Ω
1/R_parallel = 0.05 + 0.04
1/R_parallel = 0.09
R_parallel = 1/0.09
R_parallel = 11.11 Ω
Finally, we can combine the 25 Ω and 11.11 Ω resistors that are in series using the formula:
R_series = R1 + R2
R_series = 25 Ω + 11.11 Ω
R_series = 36.11 Ω
Therefore, the equivalent resistance of the circuit is 36.11 Ω.