Question

Hi there! I need an explanation on how you make the standard form equation, y=5/8x, into the standard equation 5y - 8x = 0?

What I understand so far:

y = 5/8x
minus 5/8x
y - 5/8x = 0

What I'm confused on:

So I know the answer is 5y - 8x = 0, but
I'm not sure HOW you get from y - 5/8x to 5y - 8x = 0

Would anyone care to explain thoroughly?

Thank you so much!

Long story short, how do you turn y = 5/8x into a standard form equation?
WITH explanation!

Answer 1

8y-5x=0. or 5x-8y = 0 (standard form is Ax+By=C
)

Explanation:

y=5/8x

y-5/8x=0

we want 8 out of the denominator so mutiply every term by 8

8y-5x=0