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What is the gravitational force that two 100 kg persons exert on each other when standing 1 meter apart? ( Use G=6.67×10 −11 kg 2 N m 2 ​ ) 41 N 3.6,672×10 −7 N 10,000 N D ​ 6.672×10 −11 N

User J Jiang
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Answer:

6.67 × 10^-9 N.

Step-by-step explanation:

To calculate the gravitational force between two objects, we can use Newton's law of universal gravitation:

F = (G * m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant (6.67 × 10^-11 N m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.

In this case, both persons have a mass of 100 kg, and they are standing 1 meter apart. Substituting these values into the formula, we have:

F = (6.67 × 10^-11 N m^2/kg^2) * (100 kg) * (100 kg) / (1 m)^2

F = (6.67 × 10^-11 N m^2/kg^2) * 10000 kg^2 / 1 m^2

F = 6.67 × 10^-9 N

Therefore, the gravitational force that the two 100 kg persons exert on each other when standing 1 meter apart is approximately 6.67 × 10^-9 N.

User Mark Roddy
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