Question

The turntable of a music player is rotating at a rate of 80.0rpm. The period of this rotation is (A) 0.250 s (B) 0.500 s (C) 0.750 s (D) 1.00 s (E) 1.25 s

Answer 1

Step-by-step explanation:

To find the period of rotation, we can use the formula:

Period (T) = 1 / Frequency

Given that the turntable is rotating at a rate of 80.0 rpm (revolutions per minute), we need to convert this to frequency in revolutions per second before finding the period.

The conversion is as follows:

Frequency (f) = 80.0 rpm * (1 min / 60 s)

Now we can find the period:

T = 1 / f

Substituting the value of f, we have:

T = 1 / (80.0 rpm * (1 min / 60 s))

Simplifying the expression, we find:

T = 1 / (80.0 / 60) s

T = 1 / (4/3) s

T = 3/4 s

Therefore, the period of rotation is 0.75 s.

The correct answer is (C) 0.750 s.