Question

A uniform conducting rod of length 15 cm has a potential difference across its ends equal to 34 mV (millivolts). What is the magnitude of the electric field inside the conductor in units of N/C?

Answer 1

To determine the magnitude of the electric field inside the conductor, we need to utilize the formula E = V/L, where E is the electric field, V is the potential difference, and L is the length of the conductor.

Given that the potential difference (V) across the ends of the conductor is 34 mV (0.034 V) and the length (L) of the conductor is 15 cm (0.15 m), we can now calculate the electric field (E):

E = 0.034 V / 0.15 m = 0.2267 V/m = 226.7 N/C

Therefore, the magnitude of the electric field inside the conductor is 226.7 N/C.

Step-by-step explanation: