Question

The circle is centered at point (3,-4) and has a radius of length 3. What is it’s equation?

Answer 1

(x-3)^2+(y+4)^2=9

Explanation:

The equation of a circle with center at (h,k) and radius r units is found using:

(x-h)^2+(y-k)^2=r^2

The given circle is centered at the (3,-4) and has radius 3 units,The equation of this circle is obtained by substituting the given values.

This gives us:

(x-3)^2+(y-(-4))^2=3^2

We simplify to get:

(x-3)^2+(y+4)^2=9

Answer 2

The format of a circle's equation is:

`\mapsto\phantom{333}\bf{(x-h)^2+(y-k)^2=r^2}`

where (h, k) is the circle's center, and r is the radius.

Sticking in the data, we get:

`\mapsto\phantom{333}\bf{(x-3)^2+(y-(-4)^2=3^2}`

Simplify:

`\mapsto\phantom{333}\bf{(x-3)^2+(y+4)^2=9}`

Hence, this is the circle's equation.