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Using the completing-the-square method, find the vertex of the function f(x) = −3x2 + 6x − 2 and indicate whether it is a minimum or a maximum and at what point.

Maximum at (1, 1)
Minimum at (1, 1)
Maximum at (−1, 2)
Minimum at (−1, 2)

User Gaw
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1 Answer

5 votes

Answer:

Max (1,1)

Explanation:

The parabola is opening down, so this would be the highest point.

f(x) = -3
x^(2) + 6x - 2

The x for the vertex is found


(-b)/(2a) b is 6 and a is -3


(-6)/(2(-3)) =
(-6)/(-6) = 1

The x value of the vertex is 1.

To find the y value, plug 1 in for x and solve for y

-3
x^(2) + 6x - 2

-3(
1^(2)) + 6(1) -2

-3 + 6 - 2

3 - 2

1

The y value of the vertex is 1.

The ordered pair for the vertex would be (1,1).

Helping in the name of Jesus.

User Kostya Khuta
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8.8k points