Question

24. 15 cm The figure below shows a conical flask 15cm high, filled with a liquid of density 1200kg/m³. The atmospheric pressure of the surrounding is 84,000Pa. determine the pressure at the point marked X at the bottom of the flask.

(4mk)

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Answer 1

Step-by-step explanation:

To determine the pressure at point X at the bottom of the flask, we can use the hydrostatic pressure equation. The hydrostatic pressure at a certain depth in a liquid is given by:

P = P₀ + ρgh

where:

P is the pressure at the given depth,

P₀ is the atmospheric pressure at the liquid's surface,

ρ is the density of the liquid,

g is the acceleration due to gravity, and

h is the depth or height of the liquid.

In this case, the height of the liquid (h) is equal to the height of the flask, which is 15 cm or 0.15 m. The density of the liquid (ρ) is given as 1200 kg/m³. The atmospheric pressure (P₀) is 84,000 Pa.

Using the hydrostatic pressure equation, we can calculate the pressure at point X:

P = P₀ + ρgh

P = 84,000 Pa + (1200 kg/m³)(9.8 m/s²)(0.15 m)

Calculating this expression, we find:

P ≈ 84,000 Pa + 1764 Pa

P ≈ 85,764 Pa

Therefore, the pressure at point X at the bottom of the flask is approximately 85,764 Pa.