Answer:
after 2 row operations, (a, b, c, d, e) = (3, -2, 0, 5, 3)
after 3 row operations, (a, b, c, d, e) = (-2, 1, 19, -5, 3)
Explanation:
You want the intermediate results from inverting the given augmented matrix using the row operations shown.
Problem
Apparently, the problem starts with your second attachment here, and continues to your third attachment. The matrix resulting from the row operations listed on your second attachment is the matrix at the top of my first attachment. It gives (a, b, c, d, e) = (3, -2, 0, 5, 3).
Then the row operation listed in your third attachment is applied, giving the matching results at the bottom of your third attachment and my first attachment.
Continuation
Your first attachment seems to apply 3 more row operations to the matrix at the bottom of your third attachment. The result of that is shown in my second attachment. It (finally) gives the inverse of the matrix we started with. For that inverse matrix, (a, b, c, d, e) = (-2, 1, 19, -5, 3).
The difficulty here is that we expect to see an identity matrix in the left three columns of your first attachment. We believe the problem statement is in error, since it does not show that.
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Additional comment
In an effort to get all the matrices to show in as few attachments as possible, we have nested the calculator's row operation functions. Each function takes a series of arguments and produces a matrix as output. In nesting the functions, we have used the output of one row operation as input to the next, as expected by the listing of row operations in your problem statement.
The arguments for the calculator's *row+( ) function are ...
- the multiplying factor for the row
- the matrix being manipulated
- the row being multiplied
- the row the product is being added to
As my friend used to say, "tedious, but not difficult."
Caveat: If our assumption is incorrect that your first attachment is supposed to show the final result of inverting the original matrix, then we have no idea what is intended there.
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