1. Constructing the Consumption Matrix
The consumption matrix for this economy is given by:
[0.1 0.6 0.1]
[0.3 0.2 0.6]
[0 0.6 0]
This matrix represents the amount of input required from each sector to produce one unit of output in each sector. For example, to produce one unit of manufacturing, 0.1 units of manufacturing output, 0.3 units of agricultural output, and 0.6 units of services output are required.
To determine the intermediate demands created if agriculture plans to produce 100 units, we multiply the consumption matrix by the vector [100, 0, 0]. This gives us:
[0.1 0.6 0.1] * [100, 0, 0] = [10, 60, 10]
Therefore, if agriculture plans to produce 100 units, there will be an intermediate demand of 10 units from manufacturing, 60 units from agriculture, and 10 units from services.
2. Determining Production Levels for Final Demand of 18 Units in Agriculture
To determine the production levels needed to satisfy a final demand of 18 units for agriculture, with no final demand for the other sectors, we can use the formula:
X = (I - C)⁻¹F
where:
X is the vector of production levels
I is the identity matrix
C is the consumption matrix
F is the vector of final demands
In this case, we have:
I = [1 0 0]
[0 1 0]
[0 0 1]
C = [0.1 0.6 0.1]
[0.3 0.2 0.6]
[0 0.6 0]
F = [0, 18, 0]
Substituting these values into the formula, we get:
![X = (I - C)^-^1F = [3, 7, 9]](https://img.qammunity.org/2024/formulas/business/high-school/mwr5zg7i4mek3v5a2oujkhn3ywle1hzjr5.png)
Therefore, the production levels needed to satisfy a final demand of 18 units for agriculture, with no final demand for the other sectors, are 3 units in manufacturing, 7 units in agriculture, and 9 units in services.
3. Determining Production Levels for Final Demand of 18 Units in Manufacturing
To determine the production levels needed to satisfy a final demand of 18 units for manufacturing, with no final demand for the other sectors, we can use the same formula as in the previous question. In this case, we have:
F = [18, 0, 0]
Substituting this value into the formula, we get:
![X = (I - C)^-1F = [6, 9, 15]](https://img.qammunity.org/2024/formulas/business/high-school/2x0fgyrth0i7a68g4atbgl0s385mj2lsyh.png)
Therefore, the production levels needed to satisfy a final demand of 18 units for manufacturing, with no final demand for the other sectors, are 6 units in manufacturing, 9 units in agriculture, and 15 units in services.
4. Determining Production Levels for Final Demand of 18 Units in Manufacturing and Agriculture
To determine the production levels needed to satisfy a final demand of 18 units for manufacturing, 18 units for agriculture, and 0 units for services, we can use the same formula as in the previous questions. In this case, we have:
F = [18, 18, 0]
Substituting this value into the formula, we get:
X =
![(I - C)^-^1F = [12, 15, 27]](https://img.qammunity.org/2024/formulas/business/high-school/y8qenmn1mkvnb0yswdjm7vrog56if0nooj.png)
Therefore, the production levels needed to satisfy a final demand of 18 units for manufacturing, 18 units for agriculture, and 0 units for services, are 12 units in manufacturing, 15 units in agriculture, and 27 units in services.