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If the pressure exerted by a gas at 298K in a volume

of 0.044 L is 3.81 atm, how many moles of gas are
present? R= 0.0821 L'atm/mol*K

User Sarathi
by
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1 Answer

7 votes

The number of moles of gas that are present = 0.6852×10⁻²

The gas is exerting ideal gas nature and as per the ideal gas equation,

PV=nRT

P= pressure= 3.81atm

V=volume=0.044L

R=Gas constant=0.0821 L'atm/mol*K

n= number of moles of gas

T=Temperature

3.81×0.044=n×0.0821×298

n=(3.81×0.044)÷(0.0821×298)

n=0.6852×10⁻²

User Pawel
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