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Assuming that only the listed gases are present, what would be the mole fraction of oxygen gas be for each of the following situations? At the top of a mountain when the partial pressure of nitrogen is 212 torr and the partial pressure of oxygen is 57.0 torr.

User Jua
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2 Answers

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Final answer:

To find the mole fraction of oxygen gas at the top of a mountain, you need to calculate the moles of oxygen gas and the total moles of gases. Use Dalton's law of partial pressures to find the moles of oxygen gas by dividing the partial pressure of oxygen by the total pressure and multiplying it by the total moles of gases. Substitute the values to calculate the mole fraction.

Step-by-step explanation:

The mole fraction of a gas is the ratio of the moles of that gas to the total moles of all gases in the mixture. To find the mole fraction of oxygen gas in the given situation, we need to calculate the moles of oxygen gas and the total moles of gases. Given that the partial pressure of nitrogen is 212 torr and the partial pressure of oxygen is 57.0 torr, we can use Dalton's law of partial pressures to find the moles of oxygen gas:

Mole fraction of O2 = Moles of O2 / Total moles of gases

First, let's calculate the moles of oxygen gas:

Moles of O2 = (Partial pressure of O2 / Total pressure) * Total moles of gases

Moles of O2 = (57.0 torr / (57.0 torr + 212 torr)) * Total moles of gases

Now, substitute the respective values to calculate the mole fraction of oxygen gas.

User Darren C
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5 votes

Final answer:

To calculate the mole fraction of oxygen gas in a given situation, use Dalton's law of partial pressures. The mole fraction of oxygen gas in this situation is 0.212.

Step-by-step explanation:

To calculate the mole fraction of oxygen gas (O2) in the given situation, we need to use Dalton's law of partial pressures, which states that the mole fraction of a gas is equal to its partial pressure divided by the total pressure of the mixture. In this case, the partial pressure of oxygen is 57.0 torr and the partial pressure of nitrogen is 212 torr. Therefore, the mole fraction of oxygen gas would be:

XO2 = PO2 / Ptotal = 57.0 torr / (57.0 torr + 212 torr) = 0.212

User Greg Ruhl
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