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Write the equation of the circle centered at (-4,4) with a diameter of 14.

User Jbgorski
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To write the equation of a circle centered at (h, k) with a diameter of d, we can use the standard form of the equation:

(x - h)^2 + (y - k)^2 = r^2

where (h, k) represents the center of the circle and r represents the radius.

In this case, the center of the circle is (-4, 4), and the diameter is 14. The radius is half of the diameter, so the radius would be 14 / 2 = 7.

Substituting the values into the equation, we have:

(x - (-4))^2 + (y - 4)^2 = 7^2

Simplifying further:

(x + 4)^2 + (y - 4)^2 = 49

Therefore, the equation of the circle centered at (-4, 4) with a diameter of 14 is:

(x + 4)^2 + (y - 4)^2 = 49

User Oskar Birkne
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