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!50 POINTS! (3 SIMPLE GEOMETRY QUESTIONS)

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!50 POINTS! (3 SIMPLE GEOMETRY QUESTIONS) QUESTIONS BELOW | | \/-example-1
!50 POINTS! (3 SIMPLE GEOMETRY QUESTIONS) QUESTIONS BELOW | | \/-example-1
!50 POINTS! (3 SIMPLE GEOMETRY QUESTIONS) QUESTIONS BELOW | | \/-example-2
!50 POINTS! (3 SIMPLE GEOMETRY QUESTIONS) QUESTIONS BELOW | | \/-example-3
User FalloutBoy
by
8.6k points

2 Answers

4 votes

Answer:

1. a

3. a

Explanation:

In the first and second picture, notice that the hypotenuse and some leg are congruent. So we can use the HL theorem

They are the same picture btw.

In the third picture, PQ equals XY and PR equals XW this

PQR equals XYW.

User PleasantD
by
8.8k points
3 votes

Answer:

1) a) HL

2) e) HL

3) a) ΔXYW

Explanation:

In ΔPQR and ΔXYW

PQ = XY (hypotenuse)

PR = XW (leg)

ΔPQR ≅ ΔXYW by HL postulate

2) ΔRQP and ΔWYX

QP = YX (hypotenuse)

RP = WX (leg)

ΔRQP ≅ ΔWYX by HL postulate

3) PQ = XY (hypotenuse)

PR = XW (leg)

∠PRQ = ∠XYW (=90°)

ΔPQR ≅ ΔXYW

User DemiImp
by
8.0k points

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