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Let f(x) = x3 - 8x2. Find the points on the graph of f where the tangent line is horizontal. (Enter your answers as a

comma-separated list.) smaller x-value (x, y) = larger x-value ( x, y ) =

User Spechter
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1 Answer

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Explanation:

To find the points of f where we have a derivative of 0, take the derivative


(df)/(dx) = 3 {x}^(2) - 16x

Set it equal to 0.


3 {x}^(2) - 16x = 0


x(3x - 16) = 0


x = 0


x = (16)/(3)

So our answer is (0,16/3)

User Itwasntme
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