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N figure, the hanging object has a mass of m 1


=0.420 kg; the sliding block has a mass of m 2

=0.850 kg; and the pulley is a hollow cylinder with a mass of M=0.350 kg, an inner radius of R 1

=0.020 m, and an outer radius of R 2

=0.0300 m. Assume the mass of the spokes is negligible. The coefficient of kinetic friction between the block and the horizontal surface is μ k

=0.250. The pulley turns without friction on its axle. The light cord does not stretch and does not slip on the pulley. The block has a velocity of v i

=0.820 m/s toward the pulley when it passes a reference point on the table. Use energy methods to predict its speed after it has moved to a second point, 0.700 m away

User Tejas Rao
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Final answer:

To predict the speed of the block after it has moved to a second point, we can use energy methods. First, calculate the initial kinetic energy of the block using its mass and initial velocity. Then, calculate the gravitational potential energy of the block at the second point using its mass and height. Finally, use the equation for kinetic energy to find the final velocity of the block.

Step-by-step explanation:

To predict the speed of the block after it has moved to a second point, we can use energy methods. First, calculate the initial kinetic energy of the block using its mass and initial velocity. Then, calculate the gravitational potential energy of the block at the second point using its mass and height. Next, assume there is no loss of energy due to friction and solve for the final kinetic energy. Finally, use the equation for kinetic energy to find the final velocity of the block.

The equation for kinetic energy is given by K = ½mv^2, where K is the kinetic energy, m is the mass, and v is the velocity of the object. The equation for gravitational potential energy is given by PE = mgh, where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height.

Using the given values and equations, we can calculate the speed of the block after it has moved to the second point.

User Vfedorkov
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8.2k points