Question

A big pendulum goes back and forth once every \( 18.9 \mathrm{~s} \). What is the length of the pendulum? \[ \text { (Unit = m) } \]

Answer 1

The length of the pendulum is approximately 58.50 meters.

Step-by-step explanation:

The period of a pendulum can be calculated using the formula: T = 2π(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

In this case, the period is given as 18.9 s. To find the length of the pendulum, we need to rearrange the formula:

L = g(T/2π)

Plugging in the values, with g = 9.8 m/s² (approximated to 2 decimal places), we get:

L = 9.8(18.9/2π) ≈ 58.50 m

Therefore, the length of the pendulum is approximately 58.50 meters.

Answer 2

The length of the pendulum can be calculated using the formula L = (g * T^2) / (4 * pi^2). Using the given information, the length of the pendulum is 37.7 meters.

Step-by-step explanation:

The length of a pendulum can be calculated using the formula:

L = (g * T^2) / (4 * pi^2)

Where:

• L is the length of the pendulum
• g is the acceleration due to gravity
• T is the period of the pendulum

Using the given information, we can substitute T = 18.9 s into the formula and solve for L:

L = (9.8 m/s^2 * (18.9 s)^2) / (4 * 3.14^2) = 37.7 m

Therefore, the length of the pendulum is 37.7 meters.