Question

An object is thrown vertically upward with a speed of 35 m/s. Taking g=10 m/s2, the velocity of the object 2 seconds later is 15 m/s downwards

Answer 1

Step-by-step explanation:

To determine the velocity of the object 2 seconds later, we need to consider the effect of gravity on the object's motion.

When an object is thrown vertically upward, its initial velocity is positive (in the upward direction) and decreases due to the gravitational pull. At the highest point of its trajectory, the velocity becomes zero before it starts falling downward.

Given:

Initial velocity (u) = 35 m/s (positive because it is upward)

Acceleration due to gravity (g) = 10 m/s² (negative because it is downward)

Time (t) = 2 seconds

Using the equation for vertical motion:

v = u + gt

Substituting the given values:

v = 35 m/s + (-10 m/s²) × 2 s

v = 35 m/s - 20 m/s

v = 15 m/s

Therefore, the velocity of the object 2 seconds later is 15 m/s, but it's downward because the negative sign indicates the direction.