Answer:
To find the solutions for (A) AnB, (B) Buc, and (C) AnBnc, we need to first understand the notations used.
AnB represents the intersection of sets A and B, which is the set of elements that are present in both A and B.
Buc represents the union of sets B and C, which is the set of elements that are present in either B or C or both.
AnBnc represents the intersection of sets A and B complement, also known as the relative complement of B in U. This is the set of elements that are present in A but not in B.
Now, let's find the solutions for each of the given problems:
(A) AnB:
A = {1, 2, 3, 7, 8}
B = {3, 4, 5, 7, 9}
AnB = {3, 7}
Therefore, the solution for (A) AnB is {3, 7}.
(B) Buc:
B = {3, 4, 5, 7, 9}
C = {1, 3, 5, 6, 10}
Buc = {1, 3, 4, 5, 6, 7, 9, 10}
Therefore, the solution for (B) Buc is {1, 3, 4, 5, 6, 7, 9, 10}.
(C) AnBnc:
A = {1, 2, 3, 7, 8}
B = {3, 4, 5, 7, 9}
B complement = {1, 2, 6, 8, 10}
AnBnc = {1, 2, 6, 8}
Therefore, the solution for (C) AnBnc is {1, 2, 6, 8}.