26.5k views
1 vote
a nurse mixes 60 cc of a 70% saline solution with 10% saline solution to produce a 35% saline solution. how much of the 10% solution should he use?

User Liong
by
8.6k points

1 Answer

4 votes

To determine how much of the 10% saline solution the nurse should use, let's denote the amount of the 10% solution as x cc.

Given:

Volume of the 70% saline solution: 60 cc

Concentration of the 70% saline solution: 70%

Concentration of the 10% saline solution: 10%

Desired concentration of the resulting solution: 35%

To find the amount of the 10% solution, we can set up an equation based on the principle of the concentration of solutions:

(0.7 * 60 + 0.1 * x) / (60 + x) = 0.35

In this equation, we multiply the concentration of each solution by its corresponding volume and divide by the total volume of the resulting solution.

Simplifying the equation, we get:

(42 + 0.1x) / (60 + x) = 0.35

Cross-multiplying, we have:

42 + 0.1x = 0.35 * (60 + x)

Expanding the right side of the equation, we get:

42 + 0.1x = 21 + 0.35x

Moving all the x terms to one side, we have:

0.35x - 0.1x = 42 - 21

0.25x = 21

Dividing both sides by 0.25, we get:

x = 21 / 0.25

x = 84

Therefore, the nurse should use 84 cc of the 10% saline solution to mix with the 60 cc of the 70% saline solution to produce a 35% saline solution.

User Morten
by
8.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories