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We can factor 8x^2+22x+5 by grouping.
First, we need to find two numbers whose product is 8*5=40 and whose sum is 22. These numbers are 2 and 20.
Next, we rewrite the middle term 22x as 2x+20x.
8x^2 + 2x + 20x + 5
Now we group the first two terms and the last two terms together.
2x(4x+1) + 5(4x+1)
We can see that both terms have a common factor of (4x+1), so we can factor it out.
(2x+5)(4x+1)
Therefore, the factorization of 8x^2+22x+5 is (2x+5)(4x+1).