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The mean sustained wind velocity, v, can be determined by the equation v = 6.3 StartRoot 1013 minus p EndRoot, where p is the air pressure, in millibars, at the center of the hurricane. What is the approximate air pressure at the center of a hurricane when the mean sustained wind velocity is 64 meters per second? 103 millibars 194 millibars 363 millibars 910 millibars

User Djordje Tankosic
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2 Answers

16 votes
16 votes

Answer: 910

Step-by-step explanation: Did the review and got it right

User Ricardopereira
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22 votes
22 votes

Answer:

910 millibars

Explanation:

According to the Question,

  • Given That, The mean sustained wind velocity equation
    v=6.3*√(1013-p) And The mean sustained wind velocity is 64m/s (v=64) . where, p is the air pressure(in millibars).

Now, the air pressure at the center of a hurricane when the mean sustained wind velocity is 64 m/s is


64=6.3*√(1013-p)\\(64)/(6.3) = √(1013-p)\\

on squaring both sides we get,

(10.1587)² = 1012 - p ⇒ p = 908.80≈910millibar

p = 910millibars air pressure .

User TheVerse
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