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X+Y+Z=234 Y=106,X=3Z X=___? Z=___

User Tshimanga
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1 Answer

2 votes

Given the equations:

X + Y + Z = 234

Y = 106

X = 3Z

We can substitute the values of Y and X in terms of Z into the first equation to solve for Z.

X + Y + Z = 234

(3Z) + 106 + Z = 234

4Z + 106 = 234

4Z = 234 - 106

4Z = 128

Z = 128 / 4

Z = 32

Now that we have the value of Z, we can substitute it back into the equation X = 3Z to find X.

X = 3Z

X = 3(32)

X = 96

Therefore, X = 96 and Z = 32.

User Felix Arnold
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7.7k points

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