Given the equations:
X + Y + Z = 234
Y = 106
X = 3Z
We can substitute the values of Y and X in terms of Z into the first equation to solve for Z.
X + Y + Z = 234
(3Z) + 106 + Z = 234
4Z + 106 = 234
4Z = 234 - 106
4Z = 128
Z = 128 / 4
Z = 32
Now that we have the value of Z, we can substitute it back into the equation X = 3Z to find X.
X = 3Z
X = 3(32)
X = 96
Therefore, X = 96 and Z = 32.